log[4](2x+1)+log[4](2x-1)=2

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Solution for log[4](2x+1)+log[4](2x-1)=2 equation:


Simplifying
log[4](2x + 1) + log[4](2x + -1) = 2

Reorder the terms:
glo * 4(1 + 2x) + log[4](2x + -1) = 2

Reorder the terms for easier multiplication:
4glo(1 + 2x) + log[4](2x + -1) = 2
(1 * 4glo + 2x * 4glo) + log[4](2x + -1) = 2
(4glo + 8glox) + log[4](2x + -1) = 2

Reorder the terms:
4glo + 8glox + glo * 4(-1 + 2x) = 2

Reorder the terms for easier multiplication:
4glo + 8glox + 4glo(-1 + 2x) = 2
4glo + 8glox + (-1 * 4glo + 2x * 4glo) = 2
4glo + 8glox + (-4glo + 8glox) = 2

Reorder the terms:
4glo + -4glo + 8glox + 8glox = 2

Combine like terms: 4glo + -4glo = 0
0 + 8glox + 8glox = 2
8glox + 8glox = 2

Combine like terms: 8glox + 8glox = 16glox
16glox = 2

Solving
16glox = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Divide each side by '16lox'.
g = 0.125l-1o-1x-1

Simplifying
g = 0.125l-1o-1x-1

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